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A large tower is to be supported by a series of steel wires. It is estimated that the load on each wire will be 11,100 N (2500 lb f ). Determine the minimum required wire diameter assuming a factor of safety of 2 and a yield strength of 1030 MPa (150,000 psi).

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olasunkanmilesanmi

Answer:

5.24m

Explanation:

Data given

force, F= 11,100N

safety factor,N=2

yield strength, =1030MPa

To determine the minimum diameter, we first determine the working strength which is expressed as

[tex]working strength=\frac{yield strength}{safty factor}\\ Working strength =1030/2=515MPa\\[/tex]

Since also the working strength is define as the ration of the force to the area, we have

[tex]515=\frac{11100}{A}\\ A=21.55m^{2}[/tex]

hence the required diameter is given as

[tex]A=\pi d^2/4\\d=\sqrt{\frac{4*21.55 }{\pi }} \\d=5.24m[/tex]

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