Answer:
the time required for the sound to travel between the whales 0.66 S.
Explanation:
As given in the problem, the velocity of sound wave ([tex]v[/tex]) is governed by the equation
[tex]v = \sqrt{\dfrac{B}{\rho}}[/tex]
Given, [tex]B = 2.38 \times 10^{9} Pa[/tex] and [tex]\rho = 1046 Kg m^{-3}[/tex]
So for salt water, the velocity of sound wave ([tex]v_{s}[/tex]) can be written as
[tex]v_{s} = \sqrt{\dfrac{2.38 \times 10^{9}}{1046}} ms^{-1} = 1.508 \times 10^{3} ms^{-1}[/tex]
As the whales are d = 1 Km or 1000 m apart from each other, so the time ([tex]t[/tex]) required for the sound wave to travel this distance is given by
[tex]t = \dfrac{d}{v_{s}} = \dfrac{1000 m}{1.508 \times 10^{3}} = 0.66 s[/tex]
