Answer:
[tex]w_c[/tex] = 28 mm
Explanation:
Displacement from the central maximum to minimum is as deterrmined as follows;
[tex]y_m[/tex] = [tex]\frac{m \lambda D}{a}[/tex]
If first minimum (m) = 1
single- Slit width is 170 times the wavelength of the light.
i.e
a = 170 λ
[tex]y_1[/tex] = [tex]\frac{(1) \lambda (2,.4m)}{170 \lambda}[/tex]
[tex]y_1[/tex] = 0.014 m
width of the central maximum can now be determined as:
[tex]w_c[/tex] = [tex]2y_1[/tex]
[tex]w_c[/tex] = 2(0.014 m)
[tex]w_c[/tex] = 0.028 m
[tex]w_c[/tex] = 28 mm
Hence, the width (in mm) of the central maximum on a screen 2.4 m behind the slit
= 28 mm
