Answer:
U = 12 J.
Explanation:
The potential energy in a spring is given by the following formula
[tex]U = \frac{1}{2}kx^2[/tex]
where k is the spring force constant and x is the displacement from the equilibrium.
If U = 3 J when x = 0.05 m, then k is
[tex]3 = \frac{1}{2}k(0.05)^2\\k = 2400~N/m[/tex]
Using this constant, we can calculate the potential energy at x = 0.10 m:
[tex]U = \frac{1}{2}(2400)(0.1)^2 = 12 ~J[/tex]
