Answer:
The projectile is in air for 13.03 seconds.
Explanation:
Given that,
Angle of projection of the projectile, [tex]\theta=55^{\circ}[/tex]
Initial speed of the projectile, u = 78 m/s
To find,
We need to find the time of flight of the projectile.
Solution,
It is defined as the time taken by the projectile when it is in air. It is given by the formula as :
[tex]T=\dfrac{2u\ \sin\theta}{g}[/tex]
[tex]T=\dfrac{2\times 78\ \sin(55)}{9.8}[/tex]
T = 13.03 seconds
So, the projectile is in air for 13.03 seconds.
