Answer:
5.51 m
Explanation:
From the question,
The energy used to stretch the spring = the potential energy of the rock.
(1/2)ke² = mgh ................. Equation 1
Where k = spring constant, e = extension/compression, m = mass of the rock, g = acceleration due to gravity, h = height of the rock above the ground
make h the subject of the equation.
h = ke²/2mg ....................equation 2
Given: k = 5400 N/m, e = 1 m, m = 48 kg.
Constant: g = 9.8 m/s²
Substitute into equation 2
h = 5400(1²)/(2×48×9.8)
h = 5400/940.8
h = 5.51 m.
Hence the height of the rock = 5.51 m
