According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible)
Compute the probability that a randomly selected peanut M&M is not yellow.
Compute the probability that a randomly selected peanut M&M is orange or yellow.
Compute the probability that three randomly selected peanut M&M's are all red.
If you randomly select two peanut M&M's, compute that probability that neither of them are red.
If you randomly select two peanut M&M's, compute that probability that at least one of them is red.

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Answer:

Step-by-step explanation:

According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green.

Colour      Brown     Yellow      Red     Blue   Orange     Green   total

Prob           0.12          0.15         0.12     0.23    0.23         0.15        1  

The probability that a randomly selected peanut M&M is not yellow

=[tex]1-P(Yellow) = 0.85[/tex]

the probability that a randomly selected peanut M&M is orange or yellow.

= [tex]0.23+0.15=0.38[/tex]

the probability that three randomly selected peanut M&M's are all red.

= [tex](0.12)^3 = 0.001728[/tex]

(assuming large number of peanuts and thus independent )

If you randomly select two peanut M&M's, compute that probability that neither of them are red.

= [tex](1-0.12)^2\\= 0.7744[/tex]

If you randomly select two peanut M&M's, compute that probability that at least one of them is red

=[tex]1-P(both non red)\\= 1-0.88^2\\= 0.2256[/tex]