Answer:
Step-by-step explanation:
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green.
Colour Brown Yellow Red Blue Orange Green total
Prob 0.12 0.15 0.12 0.23 0.23 0.15 1
The probability that a randomly selected peanut M&M is not yellow
=[tex]1-P(Yellow) = 0.85[/tex]
the probability that a randomly selected peanut M&M is orange or yellow.
= [tex]0.23+0.15=0.38[/tex]
the probability that three randomly selected peanut M&M's are all red.
= [tex](0.12)^3 = 0.001728[/tex]
(assuming large number of peanuts and thus independent )
If you randomly select two peanut M&M's, compute that probability that neither of them are red.
= [tex](1-0.12)^2\\= 0.7744[/tex]
If you randomly select two peanut M&M's, compute that probability that at least one of them is red
=[tex]1-P(both non red)\\= 1-0.88^2\\= 0.2256[/tex]