Answer:
The value of [tex]\bar d[/tex] is -0.2.
The value of [tex]s_{\bar d}[/tex] is 0.3464.
[tex]\mu_{d}[/tex] = mean difference in body temperatures.
Step-by-step explanation:
The data for body temperatures from five different subjects measured at 8 AM and again at 12 AM are provided.
The formula of [tex]\bar d[/tex] and [tex]s_{\bar d}[/tex] are:
[tex]\bar d=\frac{1}{n}\sum (x_{1}-x_{2})[/tex]
[tex]s_{\bar d}=\sqrt{\frac{1}{n-1}\sum (d_{i}-\bar d)^{2}}[/tex]
Consider the table below.
Compute the value of [tex]\bar d[/tex] as follows:
[tex]\bar d=\frac{1}{n}\sum (x_{1}-x_{2})=\frac{1}{5}\times-1=-0.2[/tex]
Thus, the value of [tex]\bar d[/tex] is -0.2.
Compute the value of [tex]s_{\bar d}[/tex] as follows:
[tex]s_{\bar d}=\sqrt{\frac{1}{n-1}\sum (d_{i}-\bar d)^{2}}=\sqrt{\frac{0.48}{4}}=0.3464[/tex]
Thus, the value of [tex]s_{\bar d}[/tex] is 0.3464.
The variable [tex]\mu_{d}[/tex] represents the mean difference in body temperatures measured at 8 AM and again at 12 AM.
