A vector A⃗ has a magnitude of 40.0 m and points in a direction 20.0 ∘ below the positive x axis. A second vector, B⃗ , has a magnitude of 75.0 m and points in a direction 50.0 ∘ above the positive x axis.

a) Sketch the vectors A⃗ , B⃗ , and C⃗=A⃗+B⃗ .

b) Using the component method of vector addition, find the magnitude of the vector C⃗ .

c) Using the component method of vector addition, find the direction of the vector C

Respuesta :

Answer:

Explanation:

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Ver imagen Kazeemsodikisola
Ver imagen Kazeemsodikisola

The analytical method of the components allows to find the results for the questions about the sum vector are:

     a) In the attached we have a scheme of the vectors

     b) the modulus is C = 96.3 m

     c) The angle is θ = 27.0º

Given parameters

  • Vector A with modulus A = 40.0 m and an angle of θ₁ = -20º
  • Vector B has a modulus B = 75.0 m and an angle of θ₂ = 50º

To find

    a) Draw the vectors and their sum.

    b) The module.

    c) the adirection.

The sum of vectors has several methods of resolution:

  • Graphic. In this case the vectors are drawn and the second is placed on the tip of the first and the resulting vector goes from the origin of the first to the tip of the last. This method is complicated when there are several vectors.
  • Analytical. This method is very precise and is the most used when there are many vectors.

The analytical method consists:

  • Decompose each vector into its components with respect to a given reference frame, using trigonometry.
  • Find the sum of each component
  • Construct the final vector using trigonometry and the Pythagorean theorem.

In the attached we have a diagram of each vector and its sum. Let's use trigonometry to find the component of each vectors.

Vector A

            cos θ₁ = [tex]\frac{A_x}{A}[/tex]  

            sin θ₁ = [tex]\frac{A_y}{A}[/tex]  

            Aₓ = A cos θ₁

            [tex]A_y[/tex] = A sin θ₁

            Aₓ = 40 cos (-20) = 37.59 m

            [tex]A_y[/tex]= 40 sin (-20) = -13.68 m

Vector B

           cos θ₂ = [tex]\frac{B_x}{B}[/tex]  

           sin θ₂ = [tex]\frac{B_y}{B}[/tex]  

           Bₓ = B cos θ₂

           [tex]B_y[/tex] = B sin θ₂

           Bₓ = 75 cos 50 = 48.21 m

           [tex]B_y[/tex] = 75 sin 50 = 57.45 m

we add the components.

           Cₓ = Aₓ + Bₓ

           [tex]C_y = A_y + B_y[/tex]  

           Cₓ = 37.59 + 48.20 = 85.8 m

           Cy = -13.68 + 57.45 = 43.8 m

b) We use the Pythagorean theorem to find the modulus of the resultant vector.

          C² = Cₓ² + [tex]C_y^2[/tex]  

          C = [tex]\sqrt{85.8^2 + 43.8^2 }[/tex]  

         C = 96.3 m.

c) We use trigonometry to find the angle of the resultant vector.

         tan θ =[tex]\frac{C_y}{C_x}[/tex]  

         θ = tan⁻¹ [tex]\frac{C_y}{C_x}[/tex]  

         θ = tan⁻¹ [tex]\frac{43.8}{85.8}[/tex]  

         θ = 27.0º

In conclusion, using the analytical method of the components we can find the results for the questions about the sum vector are:

     a) In the attached we have a scheme of the vectors

     b) the modulus is C = 96.3 m

     c) The angle is θ = 27.0º

Learn more about vector addition here:  brainly.com/question/25681603

Ver imagen moya1316