Answer:
[tex]372.3 J/^{\circ}C[/tex]
Explanation:
First of all, we need to calculate the total energy supplied to the calorimeter.
We know that:
V = 3.6 V is the voltage applied
I = 2.6 A is the current
So, the power delivered is
[tex]P=VI=(3.6)(2.6)=9.36 W[/tex]
Then, this power is delivered for a time of
t = 350 s
Therefore, the energy supplied is
[tex]E=Pt=(9.36)(350)=3276 J[/tex]
Finally, the change in temperature of an object is related to the energy supplied by
[tex]E=C\Delta T[/tex]
where in this problem:
E = 3276 J is the energy supplied
C is the heat capacity of the object
[tex]\Delta T =29.1^{\circ}-20.3^{\circ}=8.8^{\circ}C[/tex] is the change in temperature
Solving for C, we find:
[tex]C=\frac{E}{\Delta T}=\frac{3276}{8.8}=372.3 J/^{\circ}C[/tex]
