Explanation:
Given data
Velocity v=3 m/s
Water volume flow rate V=590 m³/s
Water elevation z=90 m
Water density p=1000 kg/m³
First we need to determine the energy per unit mass
So
[tex]e_{mech:}=e_{kine:}+e_{potent:}\\e_{mech:}=e_{potent:}\\e_{mech:}=gz\\e_{mech:}=9.81m/s*90m\\e_{mech:}=882.9J/kg\\or\\e_{mech:}=0.8829kJ/kg[/tex]
Now the power generation potential is:
[tex]\\W=m.e_{mech:}\\where\\m=pV_{volume}\\So\\W=pV_{volume}e_{mech:}\\W=1000kg/m^{3}*590m^{3}/s*882.9j/kg\\W=5.21*10^{8}W\\or\\W=520911kW\\or\\W=521MW[/tex]