Answer:
17.6 N
Explanation:
The force exerted by the punter on the football is equal to the rate of change of momentum of the football:
[tex]F=\frac{\Delta p}{\Delta t}[/tex]
where
[tex]\Delta p[/tex] is the change in momentum of the football
[tex]\Delta t=0.25 s[/tex] is the time elapsed
The change in momentum can be written as
[tex]\Delta p = m(v-u)[/tex]
where
m = 0.55 kg is the mass of the football
u = 0 is the initial velocity (the ball starts from rest)
v = 8.0 m/s is the final velocity
Combining the two equations and substituting the values, we find the force exerted on the ball:
[tex]F=\frac{m(v-u)}{\Delta t}=\frac{(0.55)(8.0-0)}{0.25}=17.6 N[/tex]
