Answer:
V = 0.002524m³/kg
%Error = 0.2851
Explanation:
Using the ideal gas equation, we can determine the specific volume of nitrogen as
PV = RT
V = RT/P
Given the following data:
R = 296.8j/kg.k
T = 139k
P = 8.5Mpa
Therefore, V = (296.8j/kg.k)×(139k)/8500000
V = 0.004853m³/kg
Using the compressibility chart, we can see that the compressibility factor of Nitrogen at this state is equal to 0.52. Using this, we can find out the specific volume of nitrogen to be
Z = PV/RT
0.52 = (8500000Pa)V/(296.8J/kg⋅K)(139K)
V = 0.52×296.87×139/8500000
V = 0.002524m³/kg
%Error = V(ideal)-V(actual)/V(actual)
%Error = 0.002524-0.002002/0.002002
%Error = 0.2609
Error for this compared with the actual value is
%Error = V(ideal)-V(actual)/V(actual)
%Error = (0.004853-0.002002)/0.004853
%Error = 0.2851