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How much should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.13

Respuesta :

Larrysammz

Answer:

$425.6 is the amount that needs to be budgeted

Step-by-step explanation:

P(Y >y)=0.1 3

P( (Y − µ )/σ  > (y − 400 )/20 )=0.1 3

P(Z >( y − 400 )/20 )=0.1 3

(y − 400 )/20 ≈ 1.28

y ≈ (1.28)(20) + 400

y ≈ 425.60

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