Answer:
No effect.
Explanation:
Equation of the reaction
CO(g) + H2O(g) --> CO2(g) + H2(g)
Usually, when there are more moles of reactants in a gaseous reaction, an increase in volume will shift the equilibrium to the left in order to favor thereactanths while when there is a decrease in volume, the equilibrium will shift towards the side of the reaction with fewer moles.
But in the above equation, the number of moles of the reactant and product on both sides are the same (equal), an increase in volume will have no effect on the equilibrium.
