Extreme-sports enthusiasts have been known to jump off the top of El Capitan, a sheer granite cliff of height 910 m in Yosemite National Park. Assume a jumper runs horizontally off the top of El Capitan with speed 5.0 m/s and enjoys a freefall until she is 150 m above the valley floor, at which time she opens her parachute.how long is the jumper in freefall? ignore air resistance

Question

contestada

Respuesta :

AmeerAbdullah AmeerAbdullah · Answer 1 · 2020-03-04T02:36:10+01:00

Answer:

The jumper is in freefall for 12.447 seconds.

Explanation:

Let's start by calculating how far the jumper falls.

Initial height (on cliff) = 910 m

Final height after freefall = 150 m

Distance the jumper falls in freefall = 910 - 150 = 760 m

We can now use the equation of motion below to solve for the time:

[tex]s=u*t+\frac{1}{2} (a*t^2)[/tex]

here. acceleration = 9.81 m/s (due to gravity)

initial speed (u) = 0 m/s (because vertical speed is 0 at the start)

and distance (s) = 760 meters (as calculated above)

So for speed we get:

[tex]760=0*t+0.5(9.81*t^2)[/tex]

[tex]760=4.905t^2[/tex]

t = 12.447 seconds

andromache andromache · Answer 2 · 2022-02-19T05:10:21+01:00

The jumper is in freefall for 12.447 seconds.

Initial height (on cliff) = 910 m

Final height after freefall = 150 m

Acceleration = 9.81 m/s

Initial speed (u) = 0 m/s

The distance the jumper falls in freefall should be = 910 - 150 = 760 m

Now the time should be

[tex]760 = 0\times times + 0.5(9.8 \times t^2)\\\\760 = 4.905t^2[/tex]

t = 12.447 seconds.

Find out more information about the Distance here :brainly.com/question/21470320?referrer=searchResults