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The compound trimethylamine, (CH3)3N, is a weak base when dissolved in water. Write the Kb expression for the weak base equilibrium that occurs in an aqueous solution of trimethylamine: Kb

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anfabba15

Answer:

Kb = [OH⁻] . [C₃H₉NH⁺] / [ C₃H₉N ]

Explanation:

The equation for the reaction of trimethylamine when it is dissolved in water is:

C₃H₉N  +  H₂O ⇄ C₃H₉NH⁺ + OH⁻   Kb

1 mol of trimethylamine catches a proton from the water in order to produce trimethylamonium.

It is a base, because it give OH⁻ to the medium

Expression for Kb (Molar concentration)

Kb = [OH⁻] . [C₃H₉NH⁺] / [ C₃H₉N ]

ayfat23

The Kb expression for the weak base equilibrium that occurs in an aqueous solution of trimethylamine is [tex]Kb = [OH^{-} ] . [C_{3} H_{9} NH^{+} ] / [ C{3} H_{9} N ][/tex]

What is Molar concentration?

Molar concentration serves a way to measure the concentration of a chemical species usually in term of amount of substance per unit volume of solution.

The reaction between trimethylamine and water can be written as

[tex][OH^{-} ] . [C_{3} H_{9} NH^{+} ] / [ C{3} H_{9} N ]Kb[/tex]

But after the reaction of trimethylamine and water, we have trimethylamonium because a proton has been donated from water and the

trimethylamonium base is formed.

Therefore,  the expression for [tex]Kb = [OH^{-} ] . [C_{3} H_{9} NH^{+} ] / [ C{3} H_{9} N ][/tex]

Learn more about Molar concentration at;

https://brainly.com/question/14943051

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