A coin is placed 12.0 cm from the axis of a rotating turntable of variable speed. When the speed of the turntable is slowly increased, the coin remains fixed on the turntable until a rate of 39.0 rpm (revolutions per minute) is reached, at which point the coin slides off.

Respuesta :

Answer:

fs = m[tex]v^{2}[/tex] / R

   = mR[tex]w^{2}[/tex]    ........... where w = 2[tex]\pi[/tex]f

then fs = µsN = µs×mg = R[tex]w^{2}[/tex]

µs = R[tex]w^{2}[/tex]/g , since w = 2[tex]\pi[/tex]f = 2[tex]\pi[/tex]× 39.0

                                            = 4.084

µs = 0.12×[tex]4.084^{2}[/tex] / 9.8

     =  0.204

Explanation:

when using this equation it is important to look at the units you working with so that it would be much easier to workout the solution.