Answer:
%isotope 1 = 68.92%
%isotope 2 = 31.08 %
Explanation:
we have the following data:
misotope 1 = 62.9296 u
misotope 2 = 64.9278 u
maverage = 63.55 u
%isotope 1 = X
%isotope 2 = 100-X
the average atomic mass is equal to:
maverage = [(misotope 1x%isotope 1)+(misotope 2x%isotope 2)/100]
substituting values:
63.55 = [(62.9296 x X)+(64.9272 x (100-X))]/100
clearing the X:
X = 68.92
therefore we have to:
%isotope 1 = 68.92%
%isotope 2 = 100-68.92 = 31.08 %