Answer:
0.637 V
Explanation:
From Ohm's law,
V = IR ................ Equation 1
Where V = Voltage, I = current, R = resistance.
Also
R = Lρ/A........... Equation 2
Where L = Length of the copper wire, ρ = resistivity of the copper wire, A = cross sectional area of the copper wire.
But,
A = πd²/4.................. Equation 2
Where d = diameter.
Substitute equation 2 into equation 1
R = 4Lρ/πd²............... Equation 3
Substitute equation 3 into equation 1
V = I(4Lρ/πd²)........... Equation 4
Given: I = 7.3 A, L = 16 m, d = 2 mm = 0.002 m, π = 3.14,
constant: ρ = 1.72 x 10⁻⁸ Ωm
Substitute into equation 4
V = 7.3(4×16×1.72x10⁻⁸)/(3.14×0.002²)
V = 8.04×10⁻⁶/(1.256×10⁻⁵)
V = 0.637 V
