A basketball player is a center in the National Basketball Association and averaged 2.3 blocked shots per game during a recent season. Assume that the number of blocked shots per game follows the Poisson distribution. What is the probability that this basketball player will block exactly two shots during the next​ game? Report to THREE decimal places and report as 0.234

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Answer:

0.265

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

A basketball player is a center in the National Basketball Association and averaged 2.3 blocked shots per game during a recent season.

This means that [tex]\mu = 2.3[/tex]

What is the probability that this basketball player will block exactly two shots during the next​ game?

This is [tex]P(X = 2)[/tex]

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 2) = \frac{e^{-2.3}*(2.3)^{2}}{(2)!} = 0.265[/tex]

So the answer is 0.265.