april316
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There are 15 members of the show choir. In how many ways can you arrange 4 members in the front row when order does not matter?

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ahan151
32760 ways. Because it is a permutation it would be 15!. Which is 15*14*13*12*11*10*9*8*7*6*5*4*3*2*1 
toporc
We need to find the number of combinations of the 15 members taken 4 at a time:
[tex]15C4=\frac{15!}{4!11!}=\frac{15\times14\times13\times12}{4\times3\times2\times1}=1365[/tex]

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