Answer:
Step-by-step explanation:
When a fair coin is tossed 100 times X no of heads is binomial with n =100 and p = 0.50
Mean = np = 50 and Variance = npq = 25
so std dev = 5
When approximated to normal
X : no of heads : N(50,5)
Required probability
i) [tex]P(42≤X≤58)\\= P(41.5<X<58.5)[/tex](applying continuity correction_
= F(58.5) -F(41.5)
= 0.9554-0.0446
=0.9108
ii) [tex]P(-8/5<X<8/5)\\= F(1.6) -F(-1.6)\\= 0.00000[/tex]
c) [tex]P(X\geq 50) = P(X\geq 49.5)\\= 1-F(49.5)\\= 0.5398[/tex]
d) P(X>0)
=1-0.0000
=1