Energy required to raise the temperature of water is 2.56x10⁹ J
Explanation:
We first need to find the volume of water in the pool.
10.0 m x 4.0 m x 3.0 m = 120 m³
Next, convert this to ml
120 m³ x 1x10⁶ = 120x10⁶ ml = 1.2x10⁸ ml
Now, if we assume that the density of the water is 1g/ml, we can estimate the mass of the water.
1.2x10⁸ ml x 1 g/ml = 1.2x10⁸ g
We can now use Q = mC∆T for find the energy needed to raise the temperature of this mass of water from 20.2ºC to 28.1ºC.
Q = heat = ?
m = mass = 1.2x10⁸ g
C = specific heat of water = 4.184 J/g/deg
∆T = change in temperature = 5.1ºC
Solving for Q: Q = (1.2x10⁸ g)(4.184 J/g/deg)(5.1 deg) = 2.56x10⁹ J
Therefore, energy required to raise the temperature of water is 2.56x10⁹ J
