Maximum shear stress in the pole is 0.
Explanation:
Given-
Outer diameter = 127 mm
Outer radius,[tex]r_{2}[/tex] = 127/2 = 63.5 mm
Inner diameter = 115 mm
Inner radius, [tex]r_{1}[/tex] = 115/2 = 57.5 mm
Force, q = 0
Maximum shear stress, τmax = ?
τmax [tex]= \frac{4q}{3\pi } (\frac{r2^2 + r2r1 + r1^2}{r2^4 - r1^4} )[/tex]
If force, q is 0 then τmax is also equal to 0.
Therefore, maximum shear stress in the pole is 0.
