contestada

A velocity selector in a mass spectrometer uses a 0.150 T magnetic field. (a) What electric field strength (in volts per meter) is needed to select a speed of 4.40 ✕ 106 m/s? V/m

Respuesta :

Answer:

The electric field strength is [tex]6.6\times10^{5}\ V/m[/tex]

Explanation:

Given that,

Magnetic field = 0.150 T

Speed [tex]v= 4.40\times10^{6}\ m/s[/tex]

We need to calculate the electric field strength

Using formula of velocity

[tex]v=\dfrac{E}{B}[/tex]

[tex]E=v\times B[/tex]

Where, v = speed

B = magnetic field

Put the value into the formula

[tex]E=4.40\times10^{6}\times0.150[/tex]

[tex]E=660000\ V/m[/tex]

[tex]E=6.6\times10^{5}\ V/m[/tex]

Hence, The electric field strength is [tex]6.6\times10^{5}\ V/m[/tex]