Answer:
ΔT = 8.6 °C
Explanation:
Given data:
Specific heat of metal = 0.70 j/g.°C
Mass of metal = 8.00 g
Heat absorbed = 48.0 J
Change of temperature = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Now we will put the values in formula.
Q = m.c. ΔT
48.0 J = 0.70 j/g.°C × 8.00 g × ΔT
48.0 J = 5.6 j/°C × ΔT
ΔT = 48.0 J / 5.6 j/°C
ΔT = 8.6 °C