Respuesta :
The first step of solving a system of equations is to solve one equation for a variable. I'll solve the first one for y.
2x + y = 7 Subtract 2x from both sides
y = -2x + 7
Now, plug that y value into the y of the second equation and solve for x.
5x + y = 9 Substitute
5x + (-2x + 7) = 9 Adjust the signs to get rid of parentheses
5x - 2x + 7 = 9 Combine like terms
3x + 7 = 9 Subtract 7 from both sides
3x = 2 Divide both sides by 3
x = [tex] \frac{2}{3} [/tex]
Now, plug that into the first equation.
2x + y = 7 Substitute
2([tex] \frac{2}{3} [/tex]) + y = 7 Multiply
[tex] \frac{4}{3} [/tex] + y = 7 Subtract [tex] \frac{4}{3} [/tex] from each side
y = 5 [tex] \frac{2}{3} [/tex]
The answer to the system of equations is ([tex] \frac{2}{3} [/tex], 5 [tex] \frac{2}{3} [/tex]).
2x + y = 7 Subtract 2x from both sides
y = -2x + 7
Now, plug that y value into the y of the second equation and solve for x.
5x + y = 9 Substitute
5x + (-2x + 7) = 9 Adjust the signs to get rid of parentheses
5x - 2x + 7 = 9 Combine like terms
3x + 7 = 9 Subtract 7 from both sides
3x = 2 Divide both sides by 3
x = [tex] \frac{2}{3} [/tex]
Now, plug that into the first equation.
2x + y = 7 Substitute
2([tex] \frac{2}{3} [/tex]) + y = 7 Multiply
[tex] \frac{4}{3} [/tex] + y = 7 Subtract [tex] \frac{4}{3} [/tex] from each side
y = 5 [tex] \frac{2}{3} [/tex]
The answer to the system of equations is ([tex] \frac{2}{3} [/tex], 5 [tex] \frac{2}{3} [/tex]).
2x + y = 7
- Using elimination
5x + y = 9
__________
-3x + 0 = -2
__________
-3x = -2
x = -2/-3
x = 2/3
From 2x + y = 7, substitute, x = 2/3
2*(2/3) + y = 7
4/3 + y = 7,
y = 7 - 4/3
y = (21 - 4)/3 = 17/3
y = 17/3
x = 2/3, and y = 17/3
- Using elimination
5x + y = 9
__________
-3x + 0 = -2
__________
-3x = -2
x = -2/-3
x = 2/3
From 2x + y = 7, substitute, x = 2/3
2*(2/3) + y = 7
4/3 + y = 7,
y = 7 - 4/3
y = (21 - 4)/3 = 17/3
y = 17/3
x = 2/3, and y = 17/3