Answer:
The temperature of the gas is 1197.02 K
Explanation:
From ideal gas law;
PV = nRT
Where;
P is the pressure of the gas
V is the volume of the gas
R is ideal gas constant = 8.314 L.kPa/mol.K
T is the temperature of the gas
n is the number of moles of gas
Volume of the gas in the cylindrical container = πr²h
Given;
r = 6/2 = 3 cm = 0.03 m
h = 11 cm = 0.11 m
V = π × (0.03)² × 0.11 = 3.11 × 10⁻⁴ m³ = 0.311 L
number of moles of oxygen gas = Reacting mass / molar mass
[tex]=\frac{0.1}{32} = 0.003125, moles[/tex]
[tex]T = \frac{PV}{nR} = \frac{100X0.311}{0.003125X8.314} =1197.02K[/tex]
Therefore, the temperature of the gas is 1197.02 K
