Respuesta :
Area of shape 1 = 6 sq unit
Area of shape 2 = 30 sq unit
Area of shape 3 = 8 sq unit
Area of rocket = 44 sq unit
Step-by-step explanation:
The rocket consists if 3 shapes : triangle, rectangle and trapezium
Area of the triangle = [tex]\frac{1}{2}[/tex] X 3 X 4 = 6 sq unit [ base = 3 and height = 4]
Area of the rectangle = 10 X 3 = 30 sq unit [ length = 10 and width = 3]
Area of the trapezium = [tex]\frac{1}{2}[/tex] X ( a+b) x h [ a= 3 b= 5 and h= 2]
= [tex]\frac{1}{2}[/tex] X 8 X 2 = 8 sq unit
Hence, area of the square = 6 + 30 + 8 = 44 sq unit
Answer:
The total area of the rocket is = 44
Step-by-step explanation:
a) shape 1 is a triangle
Base = 3 and height = 4
A = 1/2bh
A = 1/2 × 3 × 4
A = 3 × 2 = 6
b) shape 2 is a rectangle
Length = 10 and width = 3
A = l × w
A = 10 × 3
A = 30
c) shape 3 is a trapezium
a = 3, b = 5, h = 2
A = 1/2(a + b)h
A = 1/2(3 + 5) 2
A = 1/2 (8) 2
A = 8
d) total area of the rocket = Area of shape 1 + area of shape 2 + area of shape 3
Total area = 6 + 30 + 8
= 44