A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temperature of the calorimeter plus contents increased from 21.36?Cto 26.37?C.Part A
Write a balanced chemical equation for the bomb calorimeter reaction.
Part B:
What is the heat of combustion per gram of phenol?Part C:
Per mole of phenol?

Respuesta :

Answer:

The balanced chemical equation:

[tex]C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)[/tex]

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

[tex]C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)[/tex]

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = [tex]T_1= 21.36^oC[/tex]

Final temperature of the calorimeter = [tex]T_2= 26.37^oC[/tex]

Heat absorbed by calorimeter = Q

[tex]Q=C\times \Delta T[/tex]

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

[tex]\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g[/tex]

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

[tex]\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol[/tex]