Respuesta :
Answer:
When Aria sold her house after eleven years it worth was $95,300.
Step-by-step explanation:
Given:
Aria paid $75,000 for her house. Its property value increased by 2.2% per year.
Now, to find the worth of Aria house when sold after eleven years.
Let the amount of house after eleven years be [tex]x.[/tex]
Amount Aria paid for her house (A) = $75,000.
Rate of property increased per year (r) = 2.2%.
Time (t) = 11 years.
Now, to get the amount of house after eleven years we put formula:
[tex]x=A\times (1+\frac{r}{100})^{11}[/tex]
[tex]x=75000\times (1+\frac{2.2}{100})^{11}[/tex]
[tex]x=75000\times (1+0.022)^{11}[/tex]
[tex]x=75000\times (1.022)^{11}[/tex]
[tex]x=75000\times 1.2704[/tex]
[tex]x=95280.[/tex]
The amount of house after eleven years to the nearest hundred dollars is $95,300.
Therefore, when Aria sold her house after eleven years it worth was $95,300.
Property amount after 11 year is $95,250
Given that;
Property amount = $75,000
Rate of growth = 2.2% annually
Number of year = 11 year
Find:
Property amount after 11 year
Computation:
A = P[1+r]ⁿ
Property amount after 11 year = 75,000[1+0.022]¹¹
Property amount after 11 year = 75,000[1.022]¹¹
Property amount after 11 year = 75,000[1.27]
Property amount after 11 year = $95,250
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