Answer and Explanation:
For a satellite of mass m, orbiting at a distance r from the center centrpetal force = gravitationa pull:
GmM/r2 =mw2r
or GM =w2r3 = (2Pi/T)2 * r3
or (T1/T2)2 = (r1/r2)3
Given TT2/T1 = 8, r1 = 2.2rmars + rmars = 3.2rmars
(r2/r1)3 = 8 2 = 64 = 43
(r2/r1) = 4
r2 = 4 * r1 = 4 *3.2rmars = 12.8rmars
So distance of the satellite from the center of Mars = 12.8rmars = 12.8 * 3.397 x 106 m = 4.348 x 107 m