Answer:
Ratio of tin to silver in the bar is 2:3
Step-by-step explanation:
We are given the following in the question:
10 kg of tin loses 1.375 kg in the water
Percentage of weight lost by tin =
[tex]\dfrac{1.375}{10}\times 100\% = 13.75\%[/tex]
5 kg of silver loses 0.375 kg
Percentage of weight lost by silver =
[tex]\dfrac{0.375}{5}\times 100\% = 7.5\%[/tex]
20 kg bar loose 2 kg in water.
Percentage of weight lost by metal =
[tex]\dfrac{2}{20}\times 100\% = 10\%[/tex]
Let x be the amount of tin and y be the amount of silver in bar.
Thus, we can find the ratio as:
[tex]\dfrac{x}{y} = \dfrac{\text{Silver's loss - Average loss}}{\text{Average loss - Tin's loss}}\\\\\dfrac{x}{y} = \dfrac{7.5-10}{10-13.75} = \dfrac{2}{3}[/tex]
is the required ratio.
