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2) A lab tech makes 150.0 mL of 0.175 M HCl in a flask.
a) How many moles of HCl are there in this solution?
b) How many (not moles but actual Cl- particles) Clions are there in the flask (not moles but actual
Cl particles)?

2 A lab tech makes 1500 mL of 0175 M HCl in a flask a How many moles of HCl are there in this solution b How many not moles but actual Cl particles Clions are t class=

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Eduard22sly

Answer:

A. 0.02625mole

B. 6.02x10^23 ions

Explanation:

A. The following were obtained from the question:

Volume = 150mL = 150/1000 = 0.15L

Molarity = 0.175M

Mole =?

Molarity = mole / Volume

Mole = Molarity x Volume

Mole = 0.175 x 0.15

Mole = 0.02625mole

B. Avogadro's hypothesis suggest that 1mole of any substance contains 6.02x10^23 molecules, atoms or ions. This implies that 1mole HCl contains 6.02x10^23 molecules.

The dissociation of HCl is given below:

HCl <==> H+ + Cl-

From the equation,

1 mole of HCl contains 1 mole of Cl-

ion and Avogadro's hypothesis suggests that 1mole of any substance contains 6.02x10^23 molecules, atoms or ions. Therefore 1mole of Cl- contains 6.02x10^23 ions.

This means that there are 6.02x10^23 ions of Cl in HCl

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