Respuesta :

Answer:

//To enter a string, and enter a pivot string, and then print in required sequence, the string from pivot string to last as first string, and printed before the left portion of string.

import java.util.Scanner;

public class Main {

 public static void main(String args[]) {

   Scanner s1 = new Scanner(System.in);

   System.out.println("Enter Main String:");

   String f1 = s1.nextLine();

   System.out.println("Enter pivot(string):");

   String piv = s1.nextLine();

   int start1 = f1.indexOf(piv);

   int end1 = piv.length()+start1;

   if (start1 == -1){

     System.out.println("Error: Sub string(Pivot) cannot be found.");

     return;

   }

   String first1 = f1.substring(0,start1-1);

   String second1 = f1.substring(end1);

   if (f1.charAt(start1-1)==' '){

     System.out.println(second1 + " " + piv + " " + first1);

     return;

   }

   System.out.println(second1 + piv + first1);

   

 }

}

Explanation:

Please check the answer section

Answer:

n = int(input("How many numbers do you need to check? "))

odd = 0

even = 0

for i in range(1, n+1):

num = int(input("Enter number: "))

if (num % 2 == 0):

 print(str(num)+ " is an even number.")

 even = even + 1

else:

 print(str(num)+ " is an odd number.")

 odd = odd + 1

print("You entered " + str(even)+ " even number(s).")

print("You entered "+ str(odd)+ " odd number(s).")

Explanation:

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