Answer:
[tex]6.88\times 10^{-6}\ C/m^2[/tex]
Explanation:
Q = Total charge = [tex]6.3\times 10^{-8}\ C[/tex]
[tex]\rho[/tex] = Surface charge density
r = Radius = 2.7 cm
A = Surface area = [tex]4\pi r^2[/tex]
Charge is given by
[tex]Q=A\rho\\\Rightarrow Q=4\pi r^2\times \rho\\\Rightarrow \rho=\dfrac{Q}{4\pi r^2}\\\Rightarrow \rho=\dfrac{6.3\times 10^{-8}}{4\pi (2.7\times 10^{-2})^2}\\\Rightarrow \rho=0.00000687706544224\\\Rightarrow \rho=6.88\times 10^{-6}\ C/m^2[/tex]
The surface charge density is [tex]6.88\times 10^{-6}\ C/m^2[/tex]
