48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51% copper alloy
Solution:
Let "x" be the kilograms of 15 % copper
Then, (120 - x) be the kilograms of 75 % copper
Then, according to question,
"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51% copper alloy
Thus we frame a equation as:
15 % of x + 75 % of (120 - x) = 51 % of 120
Solve the equation for "x"
[tex]15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48[/tex]
Thus 48 kilograms of 15 % copper used
Then, (120 - x) = (120 - 48) = 72
Thus, 72 kilograms of 75 % copper is used