a tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were styill hungry so the coach bought 6 more hamburgers and 2 more fries for $16.60. Find the cost of each.

Respuesta :

Answer:

Hamburger = $2.5

Fries = $0.80

Step-by-step explanation:

set up a system of equations

y = total cost

x = number of hamburgers

y = number of fries

[tex]24=8x+5y\\16.60=6x+2y[/tex]

find a LCF and multiply the equations. I'll be using the LCF of 5 & 2, which is 10 for y. so I will mulitilpy the first equation by 2 to get 10y and then the second by NEGATIVE 5 (-5) so when I combine both equations the y will cancle out because I'll get -10. Doing this, you should end up with this:

[tex]48=16x+10y\\-83=-30x-10y[/tex]

when you have this combine the equations to get

[tex]-35=-14x[/tex]

then divide both sides by -14 to get

[tex]2.5=x[/tex] this is the cost of one hamburger

then you plug in x into one of the original equations (I'll use the first equation)

[tex]24=8(2.5)+5y[/tex]

then solve for y to get

[tex]0.80=y[/tex] this is the cost for fry

if you plug in both the value for x and y into the original equations (like so)

[tex]24=8(2.5)+5(0.8)\\16.60=6(2.5)+2(0.8)[/tex]

you'll see that they are true (they equal one another)

this means that the cost of a hamburger is $2.50 and the cost of fries is $0.80