80 joule is momentarily stored in each spring
Solution:
Given that,
The coil springs on a car's suspension have a value of k = 64000 N/m
When the car strikes a bump the springs briefly compress by 5.0 cm (.05 m)
By compressing the spring, we apply a force over a distance
As a result we have done work on the spring
Doing work means that we have transferred energy to spring in form of elastic potential
Therefore,
k = 64000 N/m
x = 0.05m
The elastic potential energy is given as:
[tex]PE = \frac{1}{2}kx^2[/tex]
Where, "k" is the spring constant and "x" is the displacement
[tex]PE = \frac{1}{2} \times 64000 \times 0.05^2\\\\PE = 32000 \times 0.0025\\\\PE = 80[/tex]
Thus 80 joule is momentarily stored in each spring
