Answer:
331.2 grams of [tex]NO_2[/tex] are theoretically produced .
Explanation:
[tex]S + 6HNO_3\rightarrow H_2SO_4 + 6NO_2 + 2H_2O[/tex]
Moles of sulfur = 1.20 mol
Moles nitric acid = 9.90 moles
According to reaction ,1 mole of S reacts with 6 moles of sulfuric acid.
Then 1.20 moles of S will react with :
[tex]\frac{6}{1}\times 1.20 mol=7.2 moles[/tex] of nitric acid
This means that S is in limiting amount and nitric acid is in excessive amount.
So, amount of [tex]NO_2[/tex] gas will depend upon amount of S.
According to reaction, 1 m,ole of S gives 6 moles of [tex]NO_2[/tex] gas .
Then 1.20 moles of S will give:
[tex]\frac{6}{1}\times 1.20 mol=7.2 moles[/tex] of [tex]NO_2[/tex]
Mass of 7.2 moles of [tex]NO_2[/tex]
7.2 g × 46 g/mol = 331.2 g
331.2 grams of [tex]NO_2[/tex] are theoretically produced .
