Answer:
B = 9.867 * 10^-8 T
Explanation:
Given:
- Rate of accumulating charge I = 37.0 mC/s
- radial distance from center of the plate r = 7.5 cm
- magnetic constant u_o = 4*pi *10^-7 H/m
Find:
The induced magnetic field strength 7.5 cm radially outward from the center of the plates?
Solution:
- Apply Gaussian Law on the surface:
B.(dA) = u_o*I
- The surface integral is dA = (2*pi*r):
B.(2*pi*r) = u_o*I
B = u_o*I / (2*pi*r)
- Plug values in:
B = (4*pi *10^-7)*(37*10^-3) / (2*pi*0.075)
B = 9.867 * 10^-8 T
