Answer:
0.327 M is the concentration of hydrochloric acid in the final solution.
Explanation:
Case 1:
716.7 ml of 3.86 M HCl. Using a volumetric pipet, you take 119.56 ml of that solution and dilute it to 969.88 ml in a volumetric flask.
Before dilution :
[tex]M_1=3.86 M, V_1=119.56 ml[/tex]
After dilution :
[tex]M_2=?, V_2=969.88 ml[/tex]
[tex]M_1V_1=M_2V_2[/tex] ( dilution )
[tex]M_2=\frac{M_1V_1}{V_2}=\frac{3.86 M\times 119.56 mL}{969.88 mL}[/tex]
[tex]M_2=0.4758 M[/tex]
Case 2:
Now you take 100.00 ml of case 1 solution and dilute it to 145.62 ml in a volumetric flask
Before diluting it further :
[tex]M_2=0.4758 M, V_1=100.00 ml[/tex]
After dilution :
[tex]M_3=?, V_3=145.62 ml[/tex]
[tex]M_3V_3=M_2V_2[/tex] ( dilution )
[tex]M_3=\frac{M_2V_2}{V_3}=\frac{0.4758 M\times 100.00 mL}{145.62 mL}[/tex]
[tex]M_3=0.327 M[/tex]
0.327 M is the concentration of hydrochloric acid in the final solution.
