Respuesta :
Answer:
The order of the energy of the photons of given wave will be
= Ultraviolet waves > infrared waves > microwaves
Explanation:
[tex]E=h\nu =\frac{h\times c}{\lambda}[/tex]
where,
E = energy of photon
[tex]\nu [/tex] = frequency of the radiation
h = Planck's constant = [tex]6.63\times 10^{-34}Js[/tex]
c = speed of light = [tex]3\times 10^8m/s[/tex]
[tex]\lambda[/tex] = wavelength of the radiation
We have :
(a) Frequency of infrared waves = [tex]\nu _1=6.5\times 10^{13} s^{-1}[/tex]
(b) Frequency of microwaves= [tex]\nu _2=9.8\times 10^{11} s^{-1}[/tex]
(c) Frequency of ultraviolet waves = [tex]\nu _3=8.0\times 10^{15} s^{-1}[/tex]
So, the decreasing order of the frequencies of the waves will be :
[tex]\nu _3> \nu _1> \nu _2[/tex]
As we can see from the formula that energy is directly proportional to the frequency of the wave.
[tex]E\propto \nu [/tex]
So, the order of the energy of the photons of given wave will be same as their order of frequencies:
[tex]E_3>E_1>E_2[/tex]
= Ultraviolet waves > infrared waves > microwaves
