Respuesta :
Kinetic energy of the acron had =2 J
Step-by-step explanation:
Given, the chipmunks dropped an acron from the top of a tree. The acron was 0.25 kg and had a velocity of 4 m/s when it hit ground.
Kinetic energy =[tex]\frac{1}{2} m v^2[/tex]
Here m = 0.25 kg and v =4 m/s
Kinetic energy of the acron had =[tex]\frac{1}{2}\times 0.25 \times 4^2[/tex] J
= 2 J
The kinetic energy of the Chipmunk is 2 Joules.
Kinetic energy is the energy than an object possesses due to its motion. It is given by:
Kinetic Energy(KE) = (1/2)mv²
Where m is mass, v is velocity.
Given that m = 0.25 kg, v = 4 m/s, hence:
KE = (1/2)mv²
KE = (1/2) * 0.25 * 4² = 2J
The kinetic energy of the Chipmunk is 2 Joules.
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