The complete question is given below.
Question:
Kiyo and Steven are tiling the floors in an office building. Kiyo tiled [tex]\frac{3}{6}[/tex] of the floor in one office, and Steven tiled [tex]\frac{5}{12}[/tex] of the floor in another office. Write to explain how to use a benchmark fraction to determine who tiled a greater portion of a floor.
Answer:
Kiyo tiled a greater portion of a floor
Solution:
Kiyo tiled in one office = [tex]\frac{3}{6}[/tex]
Steven tiled in another office = [tex]\frac{5}{12}[/tex]
Bench mark fraction means comparing fractions with common fraction or number. Most probably we use [tex]\frac{1}{2}[/tex] as the common fraction.
Compare [tex]\frac{3}{6}[/tex] and [tex]\frac{5}{12}[/tex] using [tex]\frac{1}{2}[/tex]:
[tex]\frac{3}{6}[/tex] is equal to the fraction [tex]\frac{1}{2}[/tex].
[tex]$\frac{3}{6}=\frac{1}{2}[/tex]
[tex]$\frac{5}{12}<\frac{1}{2}[/tex]
[tex]$\Rightarrow\frac{5}{12}<\frac{3}{6}[/tex]
Steven tiled the floor < Kiyo tiled the floor.
Hence Kiyo tiled a greater portion of a floor.
