Which of the following equations have exactly one solution?
Choose all answers that apply:
Choose all answers that apply:

(Choice A)
A
-78x+52=-52x-78−78x+52=−52x−78minus, 78, x, plus, 52, equals, minus, 52, x, minus, 78

(Choice B)
B
52x+52=52x-7852x+52=52x−7852, x, plus, 52, equals, 52, x, minus, 78

(Choice C)
C
58x+52=78x-7858x+52=78x−7858, x, plus, 52, equals, 78, x, minus, 78

(Choice D)
D
58x+52=-78x-7858x+52=−78x−7858, x, plus, 52, equals, minus, 78, x, minus, 78

Respuesta :

The equations which have exactly one solution are:

Choice A: [tex]-78x+52=-52x-78[/tex]

Choice C: [tex]58x+52=78x-78[/tex]

Choice D: [tex]58x+52=-78x-78[/tex]

Explanation:

Choice A: [tex]-78x+52=-52x-78[/tex]

Adding both sides by 52x, we have,

[tex]-26x+52=-78[/tex]

Subtracting both sides by 52,

[tex]-26x=-130[/tex]

Dividing both sides by -26,

[tex]x=5[/tex]

Hence, the equation [tex]-78x+52=-52x-78[/tex] has exactly one solution.

Thus, Choice A is the correct answer.

Choice B: [tex]52 x+52=52 x-78[/tex]

Subtracting both sides by 52x,

[tex]52=-78[/tex]

Since, both sides are not equal.

It has no solution.

Thus, Option B is not the correct answer.

Choice C: [tex]58x+52=78x-78[/tex]

Subtracting both sides by 78x,

[tex]-20x+52=-78[/tex]

Subtracting both sides by 52,

[tex]-20 x=-130[/tex]

Dividing both sides by -20,

[tex]x=6.5[/tex]

Hence, the equation [tex]58x+52=78x-78[/tex] has exactly one solution.

Thus, Choice C is the correct answer.

Option D: [tex]58x+52=-78x-78[/tex]

Adding both sides by 78x,

[tex]136x+52=-78[/tex]

Subtracting both sides by 52,

[tex]136x=-130[/tex]

Dividing both sides by 136,

[tex]x=-\frac{65}{68}\\x=-0.956[/tex]

Hence, the equation [tex]58x+52=-78x-78[/tex] has exactly one solution.

Thus, Choice D is the correct answer.

Answer

a

Step-by-step explanation:

it must =180