Answer:
[tex]6.67ft/s^2[/tex]
Explanation:
We are given that
Initial velocity=u=18ft/s
Final velocity,v=38ft/s
Time=t=3 s
We have to find the average acceleration over that 3 s period.
We know that
Average acceleration,a=[tex]\frac{v-u}{t}{t}[/tex]
Using the formula
Average acceleration,a=[tex]\frac{38-18}{3}ft/s^2[/tex]
Average acceleration,a=[tex]\frac{20}{3}ft/s^2[/tex]
Average acceleration,a=[tex]6.67ft/s^2[/tex]
Hence, the average acceleration=[tex]6.67ft/s^2[/tex]
