The value of [tex]3log_{4}(2)+log_{5}(512)[/tex] is about 5.376
Step-by-step explanation:
Let us revise some rules of logarithm
- [tex]log(a)^{n}=n.log(a)[/tex]
- [tex]log_{b}(a)=\frac{log(a)}{log(b)}[/tex]
∵ The expression is [tex]3log_{4}(2)+log_{5}(512)[/tex]
- By using the 1st rule in the first term
∵ [tex]3log_{4}(2)=log_{4}(2)^{3}[/tex]
∵ 2³ = 8
∴ [tex]log_{4}(2)^{3}=log_{4}(8)[/tex]
- By using the second rule
∵ [tex]log_{4}(8)=\frac{log(8)}{log(4)}=1.5[/tex]
∵ [tex]log_{5}(512)=\frac{log(512)}{log(5)}=3.876[/tex]
- Add the two answers
∴ [tex]3log_{4}(2)+log_{5}(512)[/tex] = 1.5 + 3.876
∴ [tex]3log_{4}(2)+log_{5}(512)[/tex] = 5.376
The value of [tex]3log_{4}(2)+log_{5}(512)[/tex] is about 5.376
Learn more:
You can learn more about the logarithmic expressions in brainly.com/question/11921476
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