Respuesta :
Answer:
The minimum initial speed is 20.0 m/s.
Explanation:
Given that,
Mass of sphere = 1.40 g
Suppose a system of two small spheres, one carrying a charge of 1.70 μC and the other a charge of -4.40 μC , with their centers separated by a distance of 0.240 m .
We need to calculate the potential energy
Using formula of potential energy
[tex]P.E=\dfrac{kq_{1}q_{2}}{d}[/tex]
Put the value into the formula
[tex]P.E=\dfrac{9\times10^{9}\times1.70\times10^{-6}\times4.40\times10^{-6}}{0.240}[/tex]
[tex]P.E=-280.5\times10^{-3}\ J[/tex]
We need to calculate the minimum initial speed
Using formula of energy
[tex]K.E=-P.E[/tex]
[tex]\dfrac{1}{2}mv^2=-280.5\times10^{-3}[/tex]
Put the value into the formula
[tex]\dfrac{1}{2}\times1.40\times10^{-3}\times v^2=280.5\times10^{-3}[/tex]
[tex]v=\sqrt{\dfrac{2\times280.5\times10^{-3}}{1.40\times10^{-3}}}[/tex]
[tex]v=20.0\ m/s[/tex]
Hence, The minimum initial speed is 20.0 m/s.
